Question

Find the solution of the square root of the quantity of x plus 2 plus 4 equals 6 and determine if it is an extraneous solution.

x = 2; extraneous

x = 2; not extraneous

x = 30; extraneous

x = 30; not extraneous

Answer 1

\[\sqrt{(x+2)}+4=6\]

Answer 2

is that it?

Answer 3

yes

Answer 4

@IMStuck

Answer 5

First this is to move the 4 to the other side, leaving this:

Answer 6

\[\sqrt{(x+2)}=2\]and then square both sides to get rid of the radial sign, like this:

Answer 7

\[(\sqrt{(x+2)})^{2}=(2)^{2}\]\[x+2=4\]

Answer 8

x = 2. Is it extraneous?

Answer 9

does it work or no?

Answer 10

it works.. so its not extraneous correct? @IMStuck

Answer 11

That is correct. Your answer is the second choice down.

Answer 12

Thank you @IMStuck