Medal!!!!!!!!!!!!!! The equation of line AB is y = 5x + 1. Write an equation of a line parallel to line AB in slope-intercept form that contains point (4, 5).
y = 5x − 15 y = 5x + 15 y = 1 over 5x + 21 over 5 y = 1 over 5x − 29 over 5
@ganeshie8
@thomaster
@tester97
hey @ganeshie8
could you help me?
I would graph the first line, then graph that same line through (4 ,5) because a parallel line has the same slope. Here's the two lines graphed. See if you can find the slope-intercept equation of a line for the blue line (the one that is parallel and goes through (4,5), this is the one we are trying to figure out)
yes i see that now what to do?
dont take my username seriously
Now you just need to find the equation of a line for the blue line. It's parallel to y = 5x+1, so we know it has the same slope So we know it will be y = 5x - something, and the something will be where it intercepts the y axis, so where does it intercept the y axis?
so its y=5x-15
@NinjaDevo
Yup, you got it! :)
@NinjaDevo
can i ask ya another please
ill make a new question
Ok. I can try my best to answer it.
ok thanks
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