Medal!!!!!!!!!!!!!! The equation of line AB is y = 5x + 1. Write an equation of a line parallel to line AB in slope-intercept form that contains point (4, 5).
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
y = 5x − 15
y = 5x + 15
y = 1 over 5x + 21 over 5
y = 1 over 5x − 29 over 5
OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
@thomaster
OpenStudy (anonymous):
@tester97
OpenStudy (anonymous):
hey @ganeshie8
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
could you help me?
OpenStudy (anonymous):
I would graph the first line, then graph that same line through (4 ,5) because a parallel line has the same slope.
Here's the two lines graphed. See if you can find the slope-intercept equation of a line for the blue line (the one that is parallel and goes through (4,5), this is the one we are trying to figure out)
OpenStudy (anonymous):
yes i see that now what to do?
OpenStudy (anonymous):
dont take my username seriously
OpenStudy (anonymous):
Now you just need to find the equation of a line for the blue line.
It's parallel to y = 5x+1, so we know it has the same slope
So we know it will be y = 5x - something, and the something will be where it intercepts the y axis, so where does it intercept the y axis?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
so its y=5x-15
OpenStudy (anonymous):
@NinjaDevo
OpenStudy (anonymous):
Yup, you got it! :)
OpenStudy (anonymous):
@NinjaDevo
OpenStudy (anonymous):
can i ask ya another please
Still Need Help?
Join the QuestionCove community and study together with friends!