Question

The volume of a fish tank is 30 cubic feet. If the density is 0.3fish over feet cubed, how many fish are in the tank?

Answer 1

100

10

9

3

Answer 2

@paki @Orion1213

Answer 3

This is a conversion problem based on the ratio. \[\frac{ 0.3 fish }{ ft^3 }\] you are given the density as\[30ft^3\] You can eliminate the variable cubic feet and solve for fish

Answer 4

Example:
\[\frac{ fish }{ ft^3 } \times \frac{ ft^3 }{ 1} = fish\] As you can see the variable cubic feet cancels out if you multiply them with each other

Answer 5

Leaving you with only fish, the answer you are looking for, so perform the operation and remember that you can also check your work by seeing the resulting units.

Answer 6

i got the answer 3.3 ...so does that mean the answer would be 3..? @Johnbc

Answer 7

I think i solved it wrong.. ugh :(

Answer 8

No check your multiplication.

Answer 9

Or show how you arrived at your answer.

Answer 10

i did 0.3/30 * 30/1 I then cross multiplied and got 0.3 over 900 and divided and got 3.3... @Johnbc

Answer 11

would the answer be 9... And yes I guessed on this answer i am confused.

Answer 12

Let us try that to see how our units would be.