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Mathematics 17 Online
OpenStudy (dumbsearch2):

An object is thrown straight upward from the ground with an initial speed of 30 feet per second. Its height (h) after t seconds is given by the equation h(t) = -5t2 + 30t. Find the domain for h(t).

OpenStudy (anonymous):

all positive values of Real number including 0 (as time cannot be negative)

OpenStudy (anonymous):

\[h(t)=-5t^2+30t \ge0\rightarrow t(30-5t)\ge0\] and t>=0, then in order to have h(t)>=0 it has to be: 30-5t>=0 and then t<=6 The domain is t>=0 and t<=6, then [0,6]

OpenStudy (anonymous):

I took this from " http://openstudy.com/study#/updates/51ee7d6fe4b00daf471a18bd " @matricked i feel it is correct , is it ?

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