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Pre-Algebra
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solve 3x - 9 + x > 27
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Start of by collecting like terms on the left side, \[3x+x = 4x \implies 4x-9 > 2\] now add 9 on both sides to get rid of it on the left, \[4x>2+9 \implies 4x> 11\] divide by 4, \[x > \frac{ 11 }{ 4 }\]
Treat the > like an =. The goal is to isolate x, so I would add 9 to both sides of the equation to start out.
that answer isnt a choice
This will give you 3x+x=36 Combine like terms to get 4x=36. Divide 36 by 4 to isolate x, so x=39.
Oh I see the problem I put >2 not 27
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XD
oops. x=9
x >9
thank you guys so much
Your welcome.
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