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Mathematics 10 Online
OpenStudy (tanya123):

http://prntscr.com/43eneb

OpenStudy (nincompoop):

that's incorrect btw

OpenStudy (astrophysics):

I know lmao

OpenStudy (nincompoop):

we are not multiplying nor dividing :P

OpenStudy (astrophysics):

I was thinking 2^2014 * 2^2014

OpenStudy (zzr0ck3r):

\(2^{2014}-2^{2013}=2*2^{2013}-2^{2013}=2^{2013}\)

OpenStudy (nincompoop):

good job ZZ

OpenStudy (astrophysics):

its some ridiculous number though, with 606 decimal digits

OpenStudy (nincompoop):

did you wolfram that schit?

OpenStudy (shadowlegendx):

It is clearly 1, people please

OpenStudy (zzr0ck3r):

me?

OpenStudy (astrophysics):

Yeah i put 2^2013

OpenStudy (camerondoherty):

2^2013 - 2^2014 is a long azz number btw XD

OpenStudy (zzr0ck3r):

2^{2014} is longer

OpenStudy (camerondoherty):

607 decimal digits so much longer

OpenStudy (nincompoop):

mine is longer

OpenStudy (camerondoherty):

lol

OpenStudy (astrophysics):

\[2^\infty \]

OpenStudy (astrophysics):

dats how long mine is

OpenStudy (camerondoherty):

o.o

OpenStudy (camerondoherty):

*changes Question*

OpenStudy (nincompoop):

length = measurement = units

OpenStudy (astrophysics):

tell me moar nincompoop

OpenStudy (tanya123):

ℬrίℓℓίαηℸ Qμℯşℸίℴη rίℊℎℸ

OpenStudy (astrophysics):

Not really

OpenStudy (ikram002p):

\(\huge\cal\color{pink}{^❤ _❤❤done_❤❤^❤_❤}\)

OpenStudy (tanya123):

Answer is http://prntscr.com/43erpm I think all of you got it right

OpenStudy (ikram002p):

well ive seen much more complicated xD

OpenStudy (astrophysics):

Yeah these questions always tend to be the same.

OpenStudy (zzr0ck3r):

and when you say all of you, you mean me.

OpenStudy (zzr0ck3r):

:)

OpenStudy (ikram002p):

lolz zzr

OpenStudy (zzr0ck3r):

@Astrophysics said it was 2

OpenStudy (zzr0ck3r):

:P

OpenStudy (astrophysics):

That was a mistake! I thought we were multiplying at first >_>

OpenStudy (zzr0ck3r):

If you are an astrophysicists that gets 2 confused with 2^2013 we are all in trouble

OpenStudy (zzr0ck3r):

lol jk

OpenStudy (astrophysics):

zz! lmao

OpenStudy (zzr0ck3r):

I thought it was 2 at first as well

OpenStudy (tanya123):

I'll be back with a more intermediate question.

OpenStudy (astrophysics):

So did nin, he was acting like he knew, but he gave me a medal right away.

OpenStudy (camerondoherty):

i got it wrong :c

OpenStudy (astrophysics):

Nin doesn't know pellet

OpenStudy (camerondoherty):

o.o

OpenStudy (ikram002p):

ok @zzr0ck3r quick Qn for u , whats the remainder of 2^2013 when u divide it by 7 :P

OpenStudy (zzr0ck3r):

this was a good question, in all my years of doing math I don't think I have seen this(or a symmetrical) question.

OpenStudy (zzr0ck3r):

find a power of 2 for which has a nice remainder

OpenStudy (zzr0ck3r):

@ikram002p what level number theory class? there are a few ways to do that. you can use fermats little theorem or the long way of finding nicer ways to write it....

OpenStudy (ikram002p):

well lol i randomly posted it for fun :P dnt take it serously hehe

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