That page says that
"The mid-segment of a triangle joins the midpoints of two sides of a triangle such that its length is half the length of the third side of the triangle."
jimthompson5910 (jim_thompson5910):
So AB is half as long as YZ
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jimthompson5910 (jim_thompson5910):
similarly, BC is also a midsegment so it is half as long as XY
OpenStudy (anonymous):
Yeah I get that but like what I don't understand is in order to find XY you would have to double BC but BC is m-3, so I don't get how to double that.
jimthompson5910 (jim_thompson5910):
so you're saying
2 times (BC) = XY
2*BC = XY
2*(m-3) = m+1
jimthompson5910 (jim_thompson5910):
solve 2*(m-3) = m+1 for m
OpenStudy (anonymous):
m=4
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OpenStudy (anonymous):
i forgot to distribute so m=7
jimthompson5910 (jim_thompson5910):
yeah it's m = 7
jimthompson5910 (jim_thompson5910):
then you use m = 7 to find XY
OpenStudy (anonymous):
so the length of XY would be 8
jimthompson5910 (jim_thompson5910):
yep
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