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What is the circle's equation?
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I believe it's either B or D...
the equation of a circle centered at \((a,b)\) with radius \(r\) is \(r^2=(x-a)^2+(y-b)^2\)
A: Silly B: Silly C: Plausible, but 2? D: Plausible.
lol
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Remember what I said about the pythagorean theorem?
plug in a b and r into the equation I posted and the answer is obvious
Yea, but when I plug in 4 for the (2r^2) part, I get 64...
Why do you think there is a "2" in there? 4*4 = 16 -- Done. "Plug In" doesn't exist.
\((x-0)^2+(y-0)^2=4^2 \ = \ ?\)
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16....
\((x-0)^{2} = x^{2} \ne 0\)
Thanks for explaining it. :)
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