Question

PLEASE HELP ME! I will fan/medal.

Answer 1

If MN is the diameter of a circle with M(-3,-4) and N(-7,-14), find the center of the circle. a. (-2,-5)
b. (-4,-10)
c. (-5,-9)
d. -10,-18)

Answer 2

Use this formula ;)
\[C=\left(\frac{x_m+x_n}{2},\frac{y_m+y_n}{2}\right)\]

Answer 3

I've tried and my answer isn't one of my answer choices :/

Answer 4

\[C=\left(\frac{-3+(-7)}{2},\frac{-4+(-14)}{2}\right)\]\[C=\left(-\frac{10}{2},-\frac{18}{2}\right)\]\[\boxed{C=(-5,-9)}\]

Answer 5

See, this time I got (-4,-10) ??

Answer 6

\[-3-7=-10\]\[\frac{-10}{2}=-5\]\[-4-14=-18\]\[\frac{-18}{2}=-9\]

Answer 7

Ohhh, okay my bad! Could you help me with 3 more?

Answer 8

I can try.

Answer 9

Okay, well here's the first one.

Calculate the equation of the line between the points (-6,-1) and (2,-1).

a. y=-1
b. x=-1
c. y=-8x-1
d. y=-x-8

Answer 10

Second

Where P is (-2,6), R is (-10,4), and segment RT is a diameter of Circle P, find the coordinates of T.

a. (-4,12)
b. (6,8)
c. (8,2)
d. (8,6)

Answer 11

Third and Final

What is the y-intercept of 12x + 4y= 10?

a. 2.5
b. -3
c. 4
d. -12

Answer 12

@ikram002p last 3?

Answer 13

First, you have to use this formula to find the m\[y-y_o=m*(x-x_o)\]When you find the m, you should replace one point in \[(x_o,y_o)\]

Answer 14

Is that for the 1st one?

Answer 15

yes

Answer 16

Okay, let me try it:) Give me a minute.

Answer 17

OK

Answer 18

@D3xt3R could you help me after :)

Answer 19

@ninjasandtigers

Answer 20

It's the last 3 tiger

Answer 21

@ArmyBoy97 I can help you, but now I've to go to the GYM

Answer 22

please real quick just two questions

Answer 23

second one: RT is the diameter so passes from R, through P, to T. The distance along X from R to P will be equal to the distance along X from P to T. Same thing along Y.

Distance along X axis from R to P is +8.
Distance along Y axis from R to P is +2.

So, distance along X from P to T is +8.
Distance along Y from P to T is +2.

So T = (Xp + 8, Yp + 2) = (-2 + 8, 6 + 2) = (6, 8)

Answer 24

OK, tag me there

Answer 25

Thanks Tiger! Do you know the other two?

Answer 26

The third one is simple, the y-intercept will happens when x=0

Answer 27

Ok:)

Answer 28

sorry, i was being a pack mule with groceries :p

Answer 29

That's okay :D

Answer 30

(-6, -1) and (2, -1)
First find the slope of the line:
y2 - y1
over
x2 - x1

Once you find the slope try putting it into point-slope form:
y - y1 = m(x - x1)

Answer 31

then change the point-slope into standard form

Answer 32

Okay let me try it

Answer 33

Is there even a slope?

Answer 34

Or would it just be 1?

Answer 35

no slope :)

Answer 36

Is it y=-8x-1?

Answer 37

hold on i have to do a dba with my math teacher

Answer 38

Okay :p

Answer 39

y-intercept is where the line crosses the y-axis.

But in order to get to standard form (y = mx + b) you should put an equation is point-slope form(y - y1 = m(x - x1)

So you pick one point. Lets go with (-6, -1). Now just substitute the values into the equation:
(-6, -1)
m= slope = 0
y - (-1) = 0(x - (-6))
y + 1 = 0(x + 6)
y + 1 = 0(x + 6)
y + 1 = (0 * x) + (0 * 6)
y + 1 = 0x
y=-1

Answer 40

Ugh, I thought I had it, too!

Answer 41

haha its ok :)

Answer 42

How about this one?
What is the y-intercept of 12x + 4y= 10?
a. 2.5
b. -3
c. 4
d. -12

Answer 43

12x+4y=10
4y=-12x+10
y=-3x+5/2
y intercept = 2.5

Answer 44

I have 5 more, can you help me? You don't have to if you don't want to :p

Answer 45

yes, i can :), but my teacher will be calling me back at anytime so bear with me :D

Answer 46

I can do that! Haha. Okay:

1. Which line has the equation y=-x + 3?

a. DF
b. DE
c. GE
d. GF

2. Which has the equation x-3y=3?
a. DF
b. DE
c. GE
d. GF

Answer 47

1:b
2:c

Answer 48

@taylorsmith1234