Question

solve the system, using substation. Write the solution as an ordered pair (m,n)

2m-3n=6
m=3-2n

no solution
(-3,-4)
(0,-2)
(6,2)
(3,0)

Answer 1

I think the solution is the last one (3, 0).

Answer 2

plug m=3-2n into the first equation
\(\Large 2(3-2n)-3n=6\)

Answer 3

thats what i did and i got n=-4

Answer 4

Show us your work.

Answer 5

Did you distribute 2? It would be
\(\Large 6-2n-3n=6\)

Answer 6

It would be 4n not 2n after the 6, sorry

Answer 7

2(3-2n)-3n=6
6-6n-3n=6
6-3n=6
-3n-6-6
+6 +6
______________
-3n=12
n=-4
thats my work

Answer 8

Hmm, In the first step you have 2*-2n=-6n

Answer 9

When you distribute 2(3-2n) you should get 6-4n because 2*3 = 6 and 2 * -2n = -4n

Answer 10

flutter you're right.

Answer 11

Yeah so when you distribute out the paranthesis, you should end up getting an equation that looks like 6-4n-3n = 6. Combine what's called the "like terms" which are -4n and -3n to get -7n. So the equation looks like 6-7n = 6. Then minus 6 from both both sides and you get -7n = 0. Divide by -7 from both sides and n = 0.

Answer 12

7n-6=6
wouldn't you add?

Answer 13

wait nevermind i get it

Answer 14

You flipped the 7n and 6. It's 6-7n not 7n - 6.

Answer 15

i said i got it