Question

Factor completely: 21x3 + 35x2 + 9x + 15

(3x − 5)(7x2 − 3)

(3x − 5)(7x2 + 3)

(3x + 5)(7x2 − 3)

(3x + 5)(7x2 + 3)

Answer 1

@Lopez______RvB

Answer 2

i think you typed that incorectly if its t a power write it like this 9^7

Answer 3

All the numbers right after x are exponents. But Ill rewrite it. Hang on

Answer 4

(3x+5) (7x^2+3)

Answer 5

Factor completely: 21x^3 + 35x^2 + 9x + 15

(3x − 5)(7x^2 − 3)

(3x − 5)(7x^2 + 3)

(3x + 5)(7x^2 − 3)

(3x + 5)(7x^2 + 3)

Answer 6

to factor this particular equation, you have to take the first two terms and separate them so to speak. So like this:
(21x3 + 35x2) + (9x + 15)
for each parenthesis you can pull out elements until the inside of both are the same.
7x^2(3x+5) + 3(3x+5)
Then you take what you pulled out and put it into its own parenthesis like so:
(7x^2+3)(3x+5)

Answer 7

yup he did a better job of explaining it but yea

Answer 8

Thank you @lasttccasey

Answer 9

You're welcome @BassCatcher15