Question

solve for x: log_2(x)=5

Answer 1

Let both sides of the equation be the exponent of base 2.
\[2^{\log_{2}(x)}=2^{5} \]

Raising a number to the 5th power is the same as multiplying the number by itself 5 times. In this case, 2 raised to the 5th power is 32

then x would equal to 32.

Answer 2

\(\large \log_2 x = 5\)

Use: \(\large \log_b x = y ~~\iff~~~ b^y = x\)

\(\large 2^5 = x\)

Just raise 2 to the 5th power.

Answer 3

thanks all