Given the polynomial 6x^3 + 4x^2 - 6x - 4, what is the value of the coefficient 'k' in the factored form?

6x^3 + 4x^2 - 6x - 4 = 2(x + k)(x - k)(3x + 2)

k= ____________

Question

Given the polynomial 6x^3 + 4x^2 - 6x - 4, what is the value of the coefficient 'k' in the factored form?

6x^3 + 4x^2 - 6x - 4 = 2(x + k)(x - k)(3x + 2)

k= ____________

anonymous · Answer

@Lopez______RvB

anonymous · Answer

idk what this means but this it the best i can help on this one http://www.quickmath.com/webMathematica3/quickmath/equations/solve/basic.jsp#c=solve_stepssolveequation&v1=6x^3+%2B+4x^2+-+6x+-+4+%3D+2%28x+%2B+k%29%28x+-+k%29%283x+%2B+2%29&v2=k

anonymous · Answer

-2

anonymous · Answer

k=1

anonymous · Answer

@ipm1988 are you sure?

anonymous · Answer

@ipm1988  k=-2 if 2 was not taken as common from parenthesis after factoring...

anonymous · Answer

@TwinYang

anonymous · Answer

Please help

anonymous · Answer

i don't understand the meaning of the question.

anonymous · Answer

@zaibali.qasmi how positive are you that the answer is 1?

anonymous · Answer

just plug inn k=1 in and multiply the parenthesis if you get the same as orignal then it will be true...

anonymous · Answer

or if you want to do it step by step then 1st find a factor of this eq directly by putting some values and then use syenthetic division..