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Can someone please help me solve this problem? -2a^0(x^-6y^3z^2)^-1 _________________________ 6x^4y^-1z^3
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Question: in numerator, is it 0 exponent of a?
yes
You ... confused me, is it not that a^0 =1 for all a?
thats how the problem is shown... :?
-2a exponent 0
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=-2
okayy..... lol :)
It becomes \[\dfrac{-2}{6x^4y^{-1}z^3}\] right?
Im confused, how where you able to leave the 2 alone?
then, just plug y^-1 up to numerator and we are done Actually, the problem should be "simplify", not "solve" problem
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