Question

Help! Given f (x) = 3x^3 - 4x^2 + x-1 what is f(2)
Factor 36n^2 - 81
Simplify : mm(m^5)^0 m^-3 divided by m^6(y^3)^-3
solve : y^2 = 18

Answer 1

So there are four parts to solve here?
Given f (x) = 3x^3 - 4x^2 + x-1 what is f(2)
Factor 36n^2 - 81
Simplify : mm(m^5)^0 m^-3 divided by m^6(y^3)^-3
Solve : y^2 = 18

Answer 2

no they four differen questions

Answer 3

no they are four different questions

Answer 4

For the first one you plug in the 2 for x and solve that.

Answer 5

Yes that's what I mean. Well the first one is fairly simple.
Given f (x) = 3x^3 - 4x^2 + x-1 what is f(2)
f(2) = 3(2)^3 - 4(2)^2 + (2) - 1 Basically just plugging in 2 for all 'x' variables
f(2) = ... continue by doing the math and you should get your answer

Answer 6

Go ahead lasttccasey. No point in two helping one person haha. I'll stick around though.

Answer 7

Factor 36n^2 - 81
Since both have perfect squares you can unfoil them. Somewhat hard to explain
but the format will be (x + (#))(x + (#)) where the # can be + or -
Are you familiar with unfoiling?

Answer 8

Sorry damain94 I didn't realize anyone answered before I hit post.

Answer 9

It's fine your explanations and format are easier to understand.

Answer 10

yes I am familiar with it

Answer 11

Okay and for the third one,
Simplify : mm(m^5)^0 m^-3 divided by m^6(y^3)^-3
What is mm? is that supposed to be m*m = m^2 or is mm another variable by itself?

Answer 12

m*m

Answer 13

Simplify : (m*m(m^5)^0 m^-3) / (m^6(y^3)^-3)
Well first I'd multiply everything through.
(m*m(m^5)^0 m^-3) / (m^6(y^3)^-3) becomes
(m^-1) / (m^6*y^-9)
any negative exponents are basically 1/ that term. ex. x^-2 = 1/x^2
(1/m)/(m^6/y^9) used the above rule
y^9/m^7 multiplied through to get final answer.

Answer 14

solve : y^2 = 18
Basically just square root both sides.
y = + or - sqrt(18)