What are the x- and y-intercepts of the quadratic equation y = x2 + 2x - 3? A) x-intercepts: (3, 0) and (-1, 0) y-intercept: (0, 3) B) x-intercepts: (-3, 0) and (1, 0) y-intercept: (0, -3) C) x-intercepts: (3, 0) and (-1, 0) y-intercept: (0, -3) D) x-intercepts: (-3, 0) and (1, 0) y-intercept: (0, 3)
well for the y intercept let x = 0... and this will eliminate 2 options
and then for x-intercept plug in y = 0
then factor the quadratic to find the x intercepts...
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or... substitute an x value from the 2 choices and see if you get y = 0... if its true, try the other
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as an really cheeky option use this link to graph it https://www.desmos.com/calculator
and it's x - intercept (x-intercept,0) so u should let y=0
(x + 3)(x - 1)
x = - 3 and x = 1
So is it B or D
and find y=intercept too
so when x = 0 what is the y value in the equation..?
y = -3 when x = 0
Answer is B
Great! correct ;)
I wish i could give you both medals. thank you!
you're welcome ;)
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