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Mathematics 10 Online
OpenStudy (anonymous):

What are the x- and y-intercepts of the quadratic equation y = x2 + 2x - 3? A) x-intercepts: (3, 0) and (-1, 0) y-intercept: (0, 3) B) x-intercepts: (-3, 0) and (1, 0) y-intercept: (0, -3) C) x-intercepts: (3, 0) and (-1, 0) y-intercept: (0, -3) D) x-intercepts: (-3, 0) and (1, 0) y-intercept: (0, 3)

OpenStudy (campbell_st):

well for the y intercept let x = 0... and this will eliminate 2 options

OpenStudy (anonymous):

and then for x-intercept plug in y = 0

OpenStudy (campbell_st):

then factor the quadratic to find the x intercepts...

OpenStudy (anonymous):

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OpenStudy (campbell_st):

or... substitute an x value from the 2 choices and see if you get y = 0... if its true, try the other

OpenStudy (anonymous):

|dw:1406012399708:dw|

OpenStudy (campbell_st):

as an really cheeky option use this link to graph it https://www.desmos.com/calculator

OpenStudy (anonymous):

and it's x - intercept (x-intercept,0) so u should let y=0

OpenStudy (anonymous):

(x + 3)(x - 1)

OpenStudy (anonymous):

x = - 3 and x = 1

OpenStudy (anonymous):

So is it B or D

OpenStudy (anonymous):

and find y=intercept too

OpenStudy (campbell_st):

so when x = 0 what is the y value in the equation..?

OpenStudy (anonymous):

y = -3 when x = 0

OpenStudy (anonymous):

Answer is B

OpenStudy (anonymous):

Great! correct ;)

OpenStudy (anonymous):

I wish i could give you both medals. thank you!

OpenStudy (anonymous):

you're welcome ;)

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