if the graph of y=fa(x-b) stretches the graph of │x│by a factor of 5 ,reflects it about the x-axis ,and shifts 4 units to the right ,which of the following are correct values of a and b
A.a=-5 b=-4
B.a=5 b=-4
C.a=5 b=4
D.a=-5 b=4

Question

if the graph of y=fa(x-b) stretches the graph of │x│by a factor of 5 ,reflects it about the x-axis ,and shifts 4 units to the right ,which of the following are correct values of a and b
A.a=-5 b=-4 
B.a=5 b=-4
C.a=5 b=4
D.a=-5 b=4

neer2890 · Answer

i don't know much about graphs ..sorry
@ganeshie8 can you please help here.

anonymous · Answer

sorry not good at these  
@ganeshie8

anonymous · Answer

@IMStuck

imstuck · Answer

I'm working on it now, ok?

anonymous · Answer

ok

imstuck · Answer

I'm getting the answer to be C.  After all the translations to your graph you get this: (drawing will NOT be very good!)

imstuck · Answer

|dw:1406221898993:dw|

anonymous · Answer

can u help me with another one

imstuck · Answer

That's all I can do with that.  I'm looking at b and a to be x and y. And those are the values that match up with the graph when it translates according to your instructions.

imstuck · Answer

I can only promise to try my best with these!  Not my favorite thing (or anyone else's on OS I'm guessing!)

anonymous · Answer

ok

anonymous · Answer

can u help with rate of change

imstuck · Answer

Oh, that's slope!  I can sure try!  Whatcha got?

anonymous · Answer

let f(x)=x^2-100 .the average rat of change from x=-10 to x=10 equals
A.-100
B.100
C.0
D.200

anonymous · Answer

@IMStuck

imstuck · Answer

Ok, let me work on this...

imstuck · Answer

The way you figure this out is to plug in your two x values into the equation and find y.  The first one, x=10, gives you this:$$y=(10)^{2}-100$$$$y=100-100$$$$y=0$$

imstuck · Answer

The second one gives you this:$$y=(-10)^{2}-100$$$$y=100-100$$$$y=0$$

imstuck · Answer

The y values are both the same for those values of x, so the answer is C. 0

anonymous · Answer

CAN  u help with some more of these

imstuck · Answer

Sure!

anonymous · Answer

the rate of change of any nonlinear function is variable
A.true
B.false

imstuck · Answer

A. true.  Linear functions are constant in their rate of change; that's what makes them a straight line.  Nonlinear are not straight lines, meaning that their rate of change is not constant, it is variable.

anonymous · Answer

ok i got a few more

anonymous · Answer

let f(x)=-1/2x+15 .the average rate of change from x=-17 to x=17 equals
A.-1/2
B.17
C.1/2
D.-17

anonymous · Answer

@IMStuck

imstuck · Answer

Sorry...I'm here!

anonymous · Answer

ok

imstuck · Answer

When you plug in 17 and -17 you get y values of 13/2 and 47/2 respectively.  so the coordinates we are working with are |dw:1406223799740:dw|