Find the perimeter of the figure. Round your answer to the nearest tenth.
@sheelo_mughal
Just add all the sides lengths to get the perimeter.
So 31? @whereismymind49
Looking at the triangle formed on the left, use `a²+b²=c²` to find the diagonal on the very left. Use `a²+b²=c²`to find the diagonal on the very right. Add all the sides.
you know that 2 red vertical segments are 20 (each ), and the small segment on the left corner is 2, so `√(20² + 2² ) = the diagonal on the very left = ?` you know the 2 sides of your triangle formed on tthe right of the figure, they are 20 (vertical red) and 10 (bottom right corner) `√(20² + 10² ) = the diagonal on the very right=?`
404=left 500=right ........I think @SolomonZelman
well, left = √404 right = √500
You can find the perimeter in exact terms (without approximating the roots), or you can round up the values of the square roots to some decimal place, and then find the Perimeter. What would your teacher prefer ?
I have no idea. im doing an online class
√500 ≈ 22.36 √404 ≈ 20.10
@SolomonZelman
You can find the perimeter in exact terms (without approximating the roots), or you can round up the values of the square roots to some decimal place, and then find the Perimeter. What would your teacher prefer ?
top and bottom sides between the red segments are 19 and 19, then you have the sides that from triangles extending outside the "square looking shape" and they are 2 and 10, then you have your diagonals 22.36 and 20.10 (the red segments are not part of the perimeter.) P = 19 + 19 + 10 + 2 + 22.36 + 20.10 = `92.46`
so thats the answer? @SolomonZelman
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