A circle is defined by the equation x2 + y2 – x – 2y – = 0. What are the coordinates for the center of the circle and the length of the radius?
use this formula (x-a)^2 + (y-b)^2=r^2 you will need to complete the square to ge the answer
oh there is suposed to be a fraction after the 2y that didnt show up. after the 2y it is -11/4 as a fraction
it doesn't matter just use the formula, the fraction put it on the right hand side
when completing the square there will be more number to add or substract from both side to
what do i put in for the variables.
first group x^2 with -x, y^2 with -2y x^2-x+y^2-2y=11/4 x^-x+1/4+y^2-2y+1-1/4-1=11/4 (x-1/2)^2+(y-1)^2=11/4+1+1/4
continue
if we have x^2-bx we complete the square like this x^2-bx+(b/2)^2-(b/2)^2=(x-b/2)^2-(b/2)^2
well as i was working it out i ended up with \[x ^{2}+y ^{2}=1.75\]
No I already gave you half answer the center should be (1/2, 1) the radius is 2
oh i see where i messed up. thank you for the help
You're welcome
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