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OpenStudy (anonymous):
A circle is defined by the equation x2 + y2 – x – 2y – = 0. What are the coordinates for the center of the circle and the length of the radius?
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OpenStudy (xapproachesinfinity):
use this formula (x-a)^2 + (y-b)^2=r^2
you will need to complete the square to ge the answer
OpenStudy (anonymous):
oh there is suposed to be a fraction after the 2y that didnt show up. after the 2y it is -11/4 as a fraction
OpenStudy (xapproachesinfinity):
it doesn't matter just use the formula, the fraction put it on the right hand side
OpenStudy (xapproachesinfinity):
when completing the square there will be more number to add or substract from both side to
OpenStudy (anonymous):
what do i put in for the variables.
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OpenStudy (xapproachesinfinity):
first group x^2 with -x, y^2 with -2y
x^2-x+y^2-2y=11/4
x^-x+1/4+y^2-2y+1-1/4-1=11/4
(x-1/2)^2+(y-1)^2=11/4+1+1/4
OpenStudy (xapproachesinfinity):
continue
OpenStudy (xapproachesinfinity):
if we have x^2-bx we complete the square like this
x^2-bx+(b/2)^2-(b/2)^2=(x-b/2)^2-(b/2)^2
OpenStudy (anonymous):
well as i was working it out i ended up with \[x ^{2}+y ^{2}=1.75\]
OpenStudy (xapproachesinfinity):
No I already gave you half answer
the center should be (1/2, 1) the radius is 2
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OpenStudy (anonymous):
oh i see where i messed up. thank you for the help
OpenStudy (xapproachesinfinity):
You're welcome
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