A system of two linear equations is graphed below. Create a new equation by setting the left-hand side of the upper equation equal to the right-hand side of the lower equation. Graph the new equation below and enter the new equation in the box to the right. y=3x+3 2y=2/3x+12. Url where I found this question is https://www.khanacademy.org/math/algebra/systems-of-eq-and-ineq/systems-solutions/e/understanding-solution-methods-to-systems-of-equations
Help
It's a systems of equations
If someone explain how to do it than I promise I would other once by myself.
Setting the left-hand side of the upper equation equal to the right-hand side of the lower equation, we get y=2/3x+12 This is already in slope-intercept form, but the y-intercept of 12 is out of the range of the graph. To graph this equation, let's put it in point-slope form. We could do this by picking any x value and finding the corresponding point on the line. If we pick x=−6 and plug it into the equation, we see that the point (−6,8) lies on the line, and we can rewrite the equation in point-slope form. (y−8)= 2/3(x+6) The line goes through the point (−6,8) and has a slope of 2/3. The problem was I don't get how they solved it.
I don't get it?
I tried to solve it.
A) y=2x−1 B) 2y+x=3 Substituting A into B we get: 2 • (2x -1) +x = 3 4x -2 +x = 3 5x = 5 That video is weird and I have NO idea why it is even there.
Me too. I wish I can look up on youtube. The youtube don't have this kind problem.
This is why I was on this website.
did you tried the procedure of wolf...?
paki - is that question meant for me?
also your equations are wrong... the equations at the link provided are different...
no, that for kk
now it shows some other equations....
brb
Who ever help me. I will best response to him.
I have no word
i got x=1...
I have NO idea why this asks you to create a third equation. When solving simultaneous equations you need two DIFFERENT equations. If you have 2x + 3x = 7 you CANNOT solve it by multiplying it by by 2 or whatever other number.
It said write a new equation. lol x=1 is new equation???
This is what they say substitution and elimination always produce equations consistent with the solution of the original system.
hmm got it... let me solve now
Setting the left-hand sides of these equations equal to each other, we get y = (2/3)x+12. this equation is now in slop intercept form....
A restaurant charges $11 for a buffet plus $2 for each drink. Another restaurant charges $14 for a buffet plus $1 for each drink. The system of equations is graphed below. Part 1: What is the solution? Part 2: Show your work to verify the solution for both equations pleasehelp me someone
I know that and I tired to solve.
pinappleloveraries What are you doing posting that here?
then,,,?
that is the new equation.... now just plot the new line graph,,, and that's all...
i need help or i will fail please @wolf1728
pinappleloveraries - you should start a NEW question and not just interrupt another question
I'm leaving here - this question is just to strange.
now please close this question... thank you..
@wolf1728 are you rude...?
(y−8)=2/3(x+6 What told the answer. And it is no solution.
Still don't get how they got (y-8)=2/3(x+6) form?
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