Question

help 20 medal reward



f(x) = x^2 +6x -16
= (x-2)(x+8)
so x = 2 or x = -8
so that means that this equation has 2 real rational solutions,
meaning that g(x) must be the equation having 2 real irrational solutions

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Answer 1

Okay

Answer 2

Woah dats a lot of medals 0_o

Answer 3

its a hard question

Answer 4

Convert f(x) to vertex form?

Answer 5

So you need to complete the square silly! :O

Answer 6

i think so CX

Answer 7

So it's f(x) = x^2 + 10x + 16 right?

Answer 8

y= (x+5)^2-9 is the vertex form

Answer 9

For the general form:
\[\Large\rm x^2+\color{orangered}{b}x\]
\[\Large\rm f(x)=x^2+\color{orangered}{6}x-16\]We take half of the b coefficient and square it, that's the value that will complete the square for us.

Answer 10

\[\Large\rm \left(\frac{\color{orangered}{b}}{2}\right)^2=\left(\frac{\color{orangered}{6}}{2}\right)^2\]

Answer 11

these are the questions

Answer 12

and the answer for #1 is
f(x) = x^2 +6x -16
= (x-2)(x+8)
so x = 2 or x = -8
so that means that this equation has 2 real rational solutions,
meaning that g(x) must be the equation having 2 real irrational solutions

Answer 13

@Broskishelleh where are you getting a 10 from??

Answer 14

My original equation, I had it before
f(x) = x^2 + 10x + 16
Flvs assignments tend to be the same anyways

Answer 15

Oh I see, it is 6x here

Answer 16

Halve the 6
Half of 6 is 3
Square it
You have 9

Answer 17

@zepdrix Amirite so far

Answer 18

y = (x+3)^2 - 9 is the vertex form @jenniferjuice

Answer 19

Yep

Answer 20

Halve the 6
Half of 6 is 3
Square it
You have 9
so add and subtract 9 on right side
(x^2+6x +9) + 16- 9
y = (x+3)^2 - 9 is the vertex form

Answer 21

ohhh i see it now