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Mathematics 7 Online
OpenStudy (ibbutibbu.):

CAN SOMEONE PLEASE HELP ME?

OpenStudy (ibbutibbu.):

OpenStudy (solomonzelman):

I think you can do part A yourself.... go for it. (But you got to explain yourself, not just yes or no).

OpenStudy (ibbutibbu.):

no... because ,,, the x valuse are the same for more than one ordered pair...?

OpenStudy (ibbutibbu.):

is that right, @SolomonZelman

OpenStudy (ibbutibbu.):

@SolomonZelman ...? plz help me...

OpenStudy (solomonzelman):

yes correct, so part A is no !

OpenStudy (ibbutibbu.):

yes i was right

OpenStudy (ibbutibbu.):

but what about the ressst

OpenStudy (solomonzelman):

Part B. \(\normalsize\color{blue}{ f(x)=-x+6 }\) when you say f(4) you just plug in 4 insteaf of x, into `-x+6`, can you do that for me?

OpenStudy (solomonzelman):

instead of x.

OpenStudy (ibbutibbu.):

-2 = -x...?

OpenStudy (ibbutibbu.):

so it becomes x = 2, right...?

OpenStudy (solomonzelman):

Yes, part B is also correct, \(\normalsize\color{black}{f(4)=-2 }\) !!!

OpenStudy (ibbutibbu.):

yaay! but wut bout c

OpenStudy (solomonzelman):

For Part C it looks as though, as you just plug in p instead of x, because x is the distance from the hoop and p is also (the new) distance from the hoop.

OpenStudy (ibbutibbu.):

O_O i have no idea what that means

OpenStudy (solomonzelman):

Looks like it should be, \(\normalsize\color{black}{f(x)=-p+6 }\), but it wouldn't make sense. I am kind of stuck on this part. Sorry-:(

OpenStudy (ibbutibbu.):

me too lolz but thx anyway

OpenStudy (solomonzelman):

Did whatever I can, I have some very significant 'holes' in my knowledge in math.... you welcome though.

OpenStudy (ibbutibbu.):

lol

OpenStudy (ibbutibbu.):

I NEEED HELP ON PART C

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