Question

Give an equation of the line through the points (3, –1) and (0, 6).

Answer 1

I came up with y=-7/3x+8

Answer 2

hmm what did you get for the slope?

Answer 3

-7/3

Answer 4

hmm ok so slope is 7/3 right

and let's say let us use the 2nd point, (0, 6)
\(\bf y-6=\frac{7}{3}(x-0)\implies y-6=\frac{7}{3}x\implies y=\frac{7}{3}x+6\)

Answer 5

OK this is what i did
y-(-1)=-7/3(x-3)
y-(-1)=-7/3x+7
y=-7/3x+8

What did I do wrong?

Answer 6

actually... should be negative 7/3 shoot lemme redo that

Answer 7

Alright (-:

Answer 8

anyhow \(\bf y-6=-\frac{7}{3}(x-0)\implies y-6=-\frac{7}{3}x\implies y=-\frac{7}{3}x+6\)

in your case using the 1st point

y-(-1)=-7/3(x-3)
y-(-1)=-7/3x+7 -----> y+1=-7/3+7 => y= -7/3 +7 -1
y=-7/3x+8

Answer 9

Alright so I solved it correct?

Answer 10

well lemme do it using the 1st point \(\bf y-({\color{brown}{ -1}})=-\frac{7}{3}(x-3)\implies y{\color{brown}{ +1}}=-\frac{7}{3}x+7\implies y=-\frac{7}{3}x+7{\color{brown}{ -1}}\)

Answer 11

OHHH OK it's
y=-7/3x+6!
Thank you!!!

Answer 12

yw