Question

0.3k^2-0.6k=2.4

Answer 1

0.3k^2-0.6k=2.4
0.3k^2 - 0.6k - 2.4 = 0
divide by 0.3
k^2 - 2k - 8 = 0
k^2 - 4k + 2k - 8 = 0
k(k-4) + 2(k-4) = 0
(k-4)(k+2) = 0
k = -2 or 4.

Answer 2

Are there any restrictions?
Because it could be both

Answer 3

thank you again and no. can you help me with a couple more? i dont understand this.

Answer 4

I can try one more.

Answer 5

2v^2+3v=4

Answer 6

2v^2+3v=4
2v^2 + 3v - 4 = 0
Plug it into the quadratic formula

Answer 7

\(\Large \Large \frac{ -b \pm \sqrt{b ^{2} - 4ac} }{ 2a } \)

Answer 8

is that the answer?

Answer 9

No, you have to plug in the values for a, b and c into that formula.
2v^2 + 3v - 4 = 0
a = 2, b = 3, c = -4
\(\Large \frac{ -3 \pm \sqrt{3 ^{2} - 4(2)(-4)} }{ 2(2) } =
\frac{ -3 \pm \sqrt{9+32} }{ 4 } = \frac{ -3 \pm \sqrt{41} }{ 4 } \\ \Large
x = \frac{ -3 + \sqrt{41} }{ 4 }; x = \frac{ -3 - \sqrt{41} }{ 4 }
\)

Answer 10

thank you so much i really appreciate it

Answer 11

you are welcome.