Adrian's CD player can hold six disks at a time and shuffles all of the albums and their songs. If he has thirteen CD's, how many different combinations of six CD's can he put in the player?

Question

Adrian's CD player can hold six disks at a time and shuffles all of the albums and their songs.  If he has thirteen CD's, how many different combinations of six CD's can he put in the player?

kropot72 · Answer

The number of combinations of n different things taken r at a time is:
$$\large C(n, r)=\frac{n!}{r!(n-r)!}$$
In this case n = 13 and r = 6. Just plug these into the formula.

anonymous · Answer

I do not know how to work the problem out.

kropot72 · Answer

$$\large C(13, 6)=\frac{13\times12\times11\times10\times9\times8}{6\times5\times4\times3\times2\times1}=you\ can\ calculate$$