Question

Please help! Given that f(x) = x2 + 3x + 6 and g(x) = the quantity of x plus two, over three, solve for f(g(x)) when x = 1.

Answer 1

−1

0

3

4


answer choices

Answer 2

well 1st find g(1) by substituting x = 1 into g(x)

then when you get that value substitute it into f(x)

Answer 3

but the answer isn't on the list

Answer 4

so like f(X)=1+2/3

Answer 5

@campbell_st

Answer 6

well I've assumed

\[g(x) = \frac{x + 2}{3}\]

so what do you get when x = 1

Answer 7

its actually x-3 over 2

Answer 8

@campbell_st

Answer 9

well that changes it

so

\[g(x) = \frac{x - 3}{2}\]

substitute x = 1 and what do you get..?

Answer 10

then substitute the answer into f(x)