given: $$\left[\begin{matrix}1-i & 1 \ -2 & -1-i\end{matrix}\right]\left[\begin{matrix}x_1 \ x_2\end{matrix}\right]=\left[\begin{matrix}0 \ 0\end{matrix}\right]$$

how do I solve for x_1 and x_2? I have the solution vector: $$\left[\begin{matrix}1-i \ 2i\end{matrix}\right]$$ I just need help figuring out how to get it.

Question

given: $$\left[\begin{matrix}1-i & 1 \ -2 & -1-i\end{matrix}\right]\left[\begin{matrix}x_1 \ x_2\end{matrix}\right]=\left[\begin{matrix}0 \ 0\end{matrix}\right]$$ 

how do I solve for x_1 and x_2? I have the solution vector: $$\left[\begin{matrix}1-i \ 2i\end{matrix}\right]$$ I just need help figuring out how to get it.

anonymous · Answer

Anybody? It seems harder than normal systems of equations...

anonymous · Answer

@mathstudent55 @dumbcow  Sorry to bother you guys but nobodys looked at this  yet :(

anonymous · Answer

I feel like its gotta be something simple, I just always seem to get an x_1 or x_2 on both sides and so I know Im making mistakes..

dumbcow · Answer

hmm det = 0 so inverse does not exist

if you try to solve with substitution you get 0=0
yet the solution is correct

anonymous · Answer

huh, ok. Thats exactly what was happening to me. 0=0.