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\(\normalsize\color{blue}{ f(x)= x^4-45x^2-196 }\) to solve for zero, set the function equal to zero, \(\normalsize\color{blue}{ x^4-45x^2-196=0 }\) THEN, \(\normalsize\color{blue}{ \rm{let~~~x^2=a} }\) The rest is easy.
Let me know if you need farther assistance.
Ok. Should I then use synthetic division?
No, just substitute \(\normalsize\color{blue}{ a }\) for \(\normalsize\color{blue}{ x^2 }\) and re-write the equation, (you should get a quadratic).
Yes, then factor?
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