Question

@jim_thompson5910

http://cyh.leeschools.net/UserContent/Documents/AP%20CalcBC%20SumAssign%2014-15.pdf

Answer 1

we can do number one together

Answer 2

what I am going to do is give you another problem, which I will solve and then you follow with yours

Answer 3

I've already done all of Part 1 with Jim and now we're continuing part 2 tonight, but thanks for the offer!

Answer 4

you should be more specific next time

Answer 5

Well that's why I tagged Jim lol because we've already been working together on it

Answer 6

so have you learned integration yet?

Answer 7

And he knows where we are in it

Answer 8

oh okay I am leaving then

Answer 9

Yes I have lol I took AP Calc AB already

Answer 10

so why do you need help then?

Answer 11

Because this is like by AB review for BC and I didn't understand a lot in AB and Jim has really helped me understand everything and gave me some confidence that I'll be able to do really well in BC with some solid review and understanding from AB.

Answer 12

you can try to learn :)
http://finedrafts.com/files/CUNY/math/calculus/Larson%20etal%209th%20ed/

Answer 13

we're at "AP Calculus BC – Part 2" I think

Answer 14

ok so for #1, you first need to find out where those two graphs intersect

this is where the calculator comes in handy

Answer 15

I already am learning. For all the help Jim has given me/will give me in the future with Calc, Statistics and Physics, I should probably be paying him to be honest.

Answer 16

yeah you should because he probably had to pay for his tuition learning these
imagine student loans?

Answer 17

And yes that's where we are and YAY I get to use my new calculator for real math so exciting!

Answer 18

I'm putting in y=x^3/1+x^2 and it says I'm putting it in wrong lol

Any suggestions?

Answer 19

you have to use parenthesis to tell the calculator to divide by all of 1+x^2

Answer 20

so y1 = (x^3)/(1+x^2)

Answer 21

Oh I got it nevermind :P

That's what I did it fixed it

Answer 22

Okay so do I jut trace it to find the intersecting point or is there a button on my calculator or something lol

Answer 23

I believe they intersect at (1.515,0.970) though

Answer 24

you can use the "intersect" feature to jump straight to the intersection point and not trace

Answer 25

x = 1.515 is close, but not quite

Answer 26

Ooo how can I get to this feature lol

Answer 27

you have a ti-84 right?

Answer 28

Yes TI-84+C

Answer 29

I found it! Lol

Answer 30

i'm sure you went to 2nd ---> trace to get the intersect feature

Answer 31

Yeah but it didnt do anything when I picked enter on intersect

Answer 32

it should show the graphs after you hit enter

Answer 33

It shows me where the 4-2x intersects at (0,4) lol

and it says on the bottom

First curve?

x=0 y=4

Answer 34

you pick each curve

then you pick a good guess that's close to the intersection point

Answer 35

How do I "pick each curve" lol

Answer 36

by hitting enter

Answer 37

basically you find the intersection menu, then hit enter 3 times (2 for the curves, 1 for the guess)

Answer 38

turns out that in this case, the guess is pretty close to where it initializes

however, sometimes you'll need to get closer to the intersection point

Answer 39

Oh I hit it 4 times and it shoes me exactly where

Answer 40

1.488,1.025

Answer 41

I'm getting this

Answer 42

Yes I got that too but in AP you have to use 3 decimal points and appropriatly round

Answer 43

alright

Answer 44

Okay so finding the area, isnt it something like subtracting the integrals or something?

Answer 45

correct