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Mathematics 15 Online
OpenStudy (anonymous):

If y varies directly as x, and y = 20 as x = 4, find the y for the x-value of 5. A) 24 B) 25 C) 26 D) 27

OpenStudy (anonymous):

@zepdrix, can you help me?

OpenStudy (imstuck):

Do you know how to write the direct variation formula?

OpenStudy (anonymous):

Nope. I have very poor math skills, unfortunately. I've tried to learn math and failed. It is like a foreign language to me.

OpenStudy (imstuck):

Oh my. Well good thing this one is pretty easy then! The direct variation formula in this case (and there are others but you only need one right now) is y = kx, where k is the constant of variation. Using the initial values of x and y they give you, you will solve for k. Then you will use that k value to find what they are asking for in the second part.

OpenStudy (imstuck):

Using y = kx and filling in our y and x, we have 20 = 4k. Can you solve that for k?

OpenStudy (anonymous):

5=k?

OpenStudy (imstuck):

Yes, that is correct! You're not bad at math! Ok...now use that k value in for the next part of the problem. They ask you to find y when x is 5. Using the direct variation formula again, we have y = kx, and y = (5)(5) (one 5 is your k value you found and the other 5 is the x value they give you). What is 5*5?

OpenStudy (anonymous):

That's simple haha, 25!

OpenStudy (imstuck):

And that's all there is to it!

OpenStudy (imstuck):

that is direct variation. Indirect, or inverse, variation is y = k/x.

OpenStudy (imstuck):

And that one is just as simple to solve. Good job! See...you're not bad at math at all!

OpenStudy (imstuck):

TY for the medal!

OpenStudy (anonymous):

Of course! Thank YOU for the help!

OpenStudy (imstuck):

You're welcome! Any time!

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