Question

log subscript 3x+2 of 125=3 HELPPPPPPPPPPPP ASAP

Answer 1

\[ \large \log_{3x+2}125=3\\
\large \implies (3x+2)^3=125\]

Answer 2

solve for x

Answer 3

PLEASE SIR HELP ME

Answer 4

I NEED THIS ANSWER SO BADD

Answer 5

@skullpatrol

Answer 6

@study100

Answer 7

@dan815

Answer 8

@wyattp17

Answer 9

@Fire_Fighter_Of_Miami

Answer 10

\[\large (3x+2)^3=(3x+2)^2(3x+2)=125\\
\large =(9x^2+12 x + 4)(3x+2)=125\\
\large =27x^3+18x^2+36x^2+24x+12x+8=125\\
\large =27x^3+54x^2+36x-117=0 \\
\large =9(3x^3+6x^2+4x-13)=0\\
\\\text{using the factor theorem, 1 is a zero of the polynomial in ( ), so (x-1) is a factor} \\
\text{then use long division to divide} 3x^3+6x^2+4x-13 \text{ into }x-1 \\
= \large 9\left[(x-1)(3x^2+9x-13) \right]=0 \\
\]
This means that \(x-1=0\) or \(3x^2+9x-13=0\)
So you can solve the 2nd equation using the quadratic formula

Answer 11

I want to thank you but its too late i hope your efforts arent in vain though

Answer 12

can someone help me solve the 2nd equation

Answer 13

I really need help im in a bad jam right now

Answer 14

\[x = \frac{-9\pm\sqrt{9^2-4(3)(-13)}}{2(3)}=\frac{-9\pm 5i\sqrt{3}}{6} \]

Answer 15

hm actually I just noticed my typo.. it should be \(+13\) not \(-13\)

Answer 16

I need to be 100% positive this is right i cant afford to screw up again i take my dba again at 1 will you still be online ?

Answer 17

I should be

Answer 18

could you help me when i take it it would be so greatly appreciated im just trying to get out of this class the math they give us is ridiculous and i have constant ridicule from my teacher and i honestly want to learn but not in this hostile enviroment

Answer 19

ok i can try

Answer 20

what class is this for?

Answer 21

Alg 2

Answer 22

i will call her back at 105 i need your help im going to review some more also

Answer 23

she expected me to solve that problem in like 2 minutes

Answer 24

Maybe trial and error? By inspection, x = 1 is a solution (the other 2 solutions are complex.. maybe you didn't cover those yet?)

Answer 25

the answers i gave her were x=125 x=58 also x=37 all wrong

Answer 26

I just need to get past this because the rest of the class are subjects i know but im stuck

Answer 27

ok

Answer 28

do you know anyone else that can help

Answer 29

Ok i will call her back you ready ?

Answer 30

ok

Answer 31

Im going to call her now

Answer 32

this is bullpellet she says i have to score higher on my test nvm

Answer 33

o.o ok

Answer 34

shes making me score high on a practice test or i cant continue in the course im sure thats breaking some type of rule

Answer 35

:S I have no idea though... I'm not even in the U.S. so I don't even know how it works there