Question

What is the vertex of the graph of y = −1(x − 2) ^2 + 3? Someone help please explain it to me.

Answer 1

y = -(x-2)^2 +3 = (-x^2 +4x -4) + 3
therefor y = - ( x^2 -4x+ 1)
then y = -{ (x-2)^2 -4 +1}
= -{(x-2)^2 - 3}
y= 3 - (x-2)^2
now we can say if (x-2)^2=0 and then y become its highest value.which is 3, (i'm not quite sure)

Answer 2

it is supposed to be a pair
(3, −2)
(−2, 3)
(3, 2)
(2, 3)

Answer 3

i think it's (2,3)

Answer 4

okay thank you