NEED HELP!!! WILL GIVE MEDAL!!! What exponential function is the best fit for the data in the table? x f(x) 1 -4 3 -1 4 3
answer choices: f(x) = 4(3)x - 1 + 4 f(x) = 4(3)x - 1 - 4 f(x) = one fourth(3)x - 1 + 4 f(x) = one fourth(3)x - 1 - 4
@ganeshie8
@cambam1323 did you try plugging in x and finding f(x)?
no i have no idea how to find these problems. will that work by plugging in for x and i get fx on the right equation? its just a matter of plugging x?
We are given this x f(x) 1 -4 3 -1 4 3 so our answer is the one that will hold true for all of these relations. You can start by putting x=1 and check f(x) for all the options, the ones which give f(x)=-4 may be the answer but the ones which are anything but -4, we can certainly ignore them. Do you follow? can you try?
yes hang on let me give it a try. i know already that the first two wont work because i tried them.
yes, take your time.
oops each x-1 is supposed to be the ^x-1 of (3)... the first two still don't work though.
could you check second option again?
sure! i was thinking the last one but it doesnt hurt to double check! :)
yes, good ;)
so it is the last one? i just double checked 2 and it didnt work.
but the last one does.
I believe second is also a possible option based on x=1 and f(x)=-4 \[f(x)=4 (x-1)^3-4\] Let's plugin x=1 \[f(x)=4 (1-1)^3-4\] \[f(x)=4\times 0 -4\] \[f(x)=0-4\longrightarrow -4\]
\[f(x)=4(3)^{x-1}-4 \] is how option two looks.
oh I am sorry, then you are correct
okay yay! thank you for helping me!!! :)
no problem. Apologies for the confusion :/
its okay that happens alot in math and technology for that matter haha
ha ha :D
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