Question

How do I graph this?

Answer 1

\[2\pm2\sqrt{22}\]

Answer 2

This is just a number. Not a function.

Answer 3

I trying to find the roots for a parabola, I used the quadratic equation for -2x^2+8x+3

Answer 4

So you're trying to plot y = -2x^2+8x+3 right?

Answer 5

yup and factoring didnt work out

Answer 6

I found the vertex (2,11)

Answer 7

plug in various x values to generate corresponding y values.

So say x = 0

y = -2x^2+8x+3
y = -2(0)^2+8(0)+3
y = 3

That means (0,3) is a point on the graph

Answer 8

if x = 1, then

y = -2x^2+8x+3
y = -2(1)^2+8(1)+3
y = 9

and (1,9) is also on the graph

Answer 9

keep going until you have enough points (at least 6 should do). Then plot all of the points on the same xy coordinate grid. Finally, draw a curve through these points to graph the function

Answer 10

what about the vertex? Do we just ignore it?

Answer 11

no you can include that as one of the points you plot

Answer 12

if anything, that's your center point so to speak

Answer 13

I got it, thanks

Answer 14

is there anything else to do after i find the points and draw the parabola?

Answer 15

nope, after that's done, you've graphed it