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Mathematics 7 Online
OpenStudy (anonymous):

given sinx=-4/5 and x is in the quadant 3 what is the value of tanx/2 I am really bad at trig

OpenStudy (anonymous):

do the cos(arcsin(-4/5)

OpenStudy (anonymous):

take the negative value of that, and put it under -4/5 as a ratio. Simplify.

OpenStudy (anonymous):

@sylbot I got 4/3

OpenStudy (anonymous):

that is good. nice job

OpenStudy (anonymous):

also another way to do it is to draw the triangle.

OpenStudy (anonymous):

|dw:1407031709569:dw| You know this is a -3,-4,5 triangle

OpenStudy (anonymous):

because it is in the third quadrant

OpenStudy (anonymous):

so the answer is -4/-3=4/3, so good job.

OpenStudy (anonymous):

This is what its giving me

OpenStudy (anonymous):

hahahah no just put in 4/3, youre good. I was just showing work :P

OpenStudy (anonymous):

@sylbot gaaahhh its still giving me the same thing, maybe it wants it in decimal form

OpenStudy (anonymous):

@sylbot it says the answer is -2

OpenStudy (anonymous):

oh whoops I goofed up.... I didn't see the tan(x/2)

OpenStudy (anonymous):

I thought it said tan(x)

OpenStudy (anonymous):

ok so what you would do is, take arcsin(-4/5) Divide that by 2. Then take the tangent of that number.

OpenStudy (anonymous):

the new angle.

OpenStudy (anonymous):

then multiply by -1 to offset the quadrant difference.

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