given sinx=-4/5 and x is in the quadant 3 what is the value of tanx/2 I am really bad at trig
do the cos(arcsin(-4/5)
take the negative value of that, and put it under -4/5 as a ratio. Simplify.
@sylbot I got 4/3
that is good. nice job
also another way to do it is to draw the triangle.
|dw:1407031709569:dw| You know this is a -3,-4,5 triangle
because it is in the third quadrant
so the answer is -4/-3=4/3, so good job.
This is what its giving me
hahahah no just put in 4/3, youre good. I was just showing work :P
@sylbot gaaahhh its still giving me the same thing, maybe it wants it in decimal form
@sylbot it says the answer is -2
oh whoops I goofed up.... I didn't see the tan(x/2)
I thought it said tan(x)
ok so what you would do is, take arcsin(-4/5) Divide that by 2. Then take the tangent of that number.
the new angle.
then multiply by -1 to offset the quadrant difference.
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