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OpenStudy (anonymous):
Thanks hahaha :) Youre great!
ganeshie8 (ganeshie8):
common stuff is just \(7!\) right ?
OpenStudy (eric_d):
yes
ganeshie8 (ganeshie8):
10! = 10x9x8x `7x6x5x4x3x2x1`
7! = `7x6x5x4x3x2x1`
can be writen as :
10! = 10x9x8x `7!`
7! = `7!`
ganeshie8 (ganeshie8):
add them both and factor that common stuff :
10! = 10x9x8x `7!`
7! = `7!`
--------------------------
10! + 7! = ?
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OpenStudy (eric_d):
the given answer is
11(9factorial)
ganeshie8 (ganeshie8):
ohk... then i guess we're only half done :
10! = 10x9x8x `7!`
7! = `7!`
--------------------------
10! + 7! = 10x9x8x `7!` + `7!`
= `7!` (10x9x8 + 1)
ganeshie8 (ganeshie8):
does that look okay, so far ?
OpenStudy (eric_d):
ys
OpenStudy (eric_d):
what's nxt
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ganeshie8 (ganeshie8):
thinking...
ganeshie8 (ganeshie8):
Alright, there seems to be a typo in the given expression, it should be :
a) 10 factorial + \(\color{red}{9}\) factorial
can you check the question again ?
OpenStudy (ikram002p):
yeah it cant be 11( 9! )
mm
OpenStudy (eric_d):
I had re-check..
There is'nt any typo
OpenStudy (eric_d):
Try this
@xapproachesinfinity
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OpenStudy (xapproachesinfinity):
So far i found only what ganesh and eyth found!
if there no typo that means we need to rewrite this 7!(721)
OpenStudy (eric_d):
Okay @xapproachesinfinity
OpenStudy (xapproachesinfinity):
let me try and see
OpenStudy (xapproachesinfinity):
7!(6!+1) nothing you can achieve here. there must be a typo!
OpenStudy (anonymous):
ganeshie8 is right there must be a typo
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