solve for x when x is a real number (x+3)(x+3)0

Question

solve for x when x is a real number (x+3)(x+3)>0

anonymous · Answer

x>-3

anonymous · Answer

Could you explain?

anonymous · Answer

well in total it would be once added 2x+3+3>0
                                                          -6     -6
                                                        2x>-6
                                                             /2
                                                           x>-3

anonymous · Answer

pretty sure i MIGHT be wrong so yeah :l

anonymous · Answer

ahh I thought i was supposed to multiply them :l

anonymous · Answer

thats what confuses me too 3:

ksaimouli · Answer

When you substitute x= -3 you will get an answer = 0 not > 0. That's why x must be greater than -3 to avoid =

anonymous · Answer

Still have no clue how to do this..

anonymous · Answer

Could it be 
x^2-9>0
x^2>9
x>3?

anonymous · Answer

After you multiply them

xapproachesinfinity · Answer

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