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Mathematics 25 Online
OpenStudy (anonymous):

solve for x when x is a real number (x+3)(x+3)>0

OpenStudy (anonymous):

x>-3

OpenStudy (anonymous):

Could you explain?

OpenStudy (anonymous):

well in total it would be once added 2x+3+3>0 -6 -6 2x>-6 /2 x>-3

OpenStudy (anonymous):

pretty sure i MIGHT be wrong so yeah :l

OpenStudy (anonymous):

ahh I thought i was supposed to multiply them :l

OpenStudy (anonymous):

thats what confuses me too 3:

OpenStudy (ksaimouli):

When you substitute x= -3 you will get an answer = 0 not > 0. That's why x must be greater than -3 to avoid =

OpenStudy (anonymous):

Still have no clue how to do this..

OpenStudy (anonymous):

Could it be x^2-9>0 x^2>9 x>3?

OpenStudy (anonymous):

After you multiply them

OpenStudy (xapproachesinfinity):

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