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Mathematics 7 Online
OpenStudy (anonymous):

What are the coordinates of the turning point for the function f(x) = (x - 2)3 + 1?

OpenStudy (anonymous):

take the derivative and equal to 0?

OpenStudy (anonymous):

how do you take the derivative

OpenStudy (anonymous):

what math problem is that i mean what class? calculus or algebra?

OpenStudy (anonymous):

algebra

OpenStudy (anonymous):

thats a line

OpenStudy (anonymous):

is it (x-2)^3 or you typed it right

OpenStudy (anonymous):

(-2, -1) (-2, 1) (2, -1) (2, 1) these are the answer choices

OpenStudy (anonymous):

and yes

OpenStudy (anonymous):

(2,1)

OpenStudy (anonymous):

if you graph it thats the only point thats on line

OpenStudy (anonymous):

oh okay

OpenStudy (anonymous):

for that function when x = -2 then y should equal -11 so first choices are wrong

OpenStudy (anonymous):

What are the possible numbers of positive, negative, and complex zeros of f(x) = -3x4 + 5x3 - x2 + 8x + 4? do you know how to do this one?

OpenStudy (anonymous):

I dont even know where to start

OpenStudy (anonymous):

Use Descartes' Rule of Sign Changes

OpenStudy (anonymous):

I dont know what that is

OpenStudy (anonymous):

ive heard of it but dont really remember

OpenStudy (anonymous):

You just count the amount of times the sign changes from positive to negative, this'll give you the amount of positive zeroes, then you change each sign to its opposite and count again and it'll give you the amount of negative zeroes. It's a bit more complicated than that but it gives you gist of it

OpenStudy (anonymous):

i think 3 positive and 2 negative?

OpenStudy (anonymous):

Positive: 2 or 0; negative: 2 or 0; complex: 4 or 2 or 0 Positive: 1; negative: 3 or 1; complex: 2 or 0 Positive: 3 or 1; negative: 1; complex: 2 or 0 Positive: 4 or 2 or 0; negative: 2 or 0; complex: 4 or 2 or 0 these ar ethe answer choices

OpenStudy (anonymous):

3 sign changes when in its original form mean there can be 3 or 1 positive zeroes 3 sign changes when the signs are changed mean there can be 3 or 1 negative zeroes Due to the degree of the function we know it has to have 4 zeroes

OpenStudy (anonymous):

So it seems like it's 3 or 1 positive, 1 negative and 2 or 0 complex

OpenStudy (anonymous):

i am not sure i never learned any of that in algebra or matter of fact i have never had problems like that till university calculus 2 ( i am taking cal 2 right now)

OpenStudy (anonymous):

That's what i figure atleast

OpenStudy (anonymous):

yeah we got same positive i would go with 3 or 1 option haha

OpenStudy (anonymous):

That's the right answer, it's Descartes' Rule, I also had this question before

OpenStudy (anonymous):

positive 3 or 1?

OpenStudy (anonymous):

okay ill look up descartes rule and see what thats all about lol

OpenStudy (anonymous):

It's the third option: 3 or 1 positive, 1 negative, 2 or 0 complex

OpenStudy (anonymous):

thank you guys!

OpenStudy (anonymous):

no problem haha

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