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Mathematics 12 Online
OpenStudy (anonymous):

calculus 2

OpenStudy (anonymous):

\[\sum n =1 \to infinity (1/(n^3+n^2)\]

OpenStudy (anonymous):

explain please?

OpenStudy (anonymous):

the answer should be ((pi^2)/6)-1 at least thats what wolfram alpha says. i am trying to figure out how

OpenStudy (xapproachesinfinity):

is that like this? \[\sum_{1}^{\infty}\frac{ 1}{ n ^{3} +n ^{2}}\]

OpenStudy (anonymous):

no where its 1 its n=1 its a series problem

OpenStudy (xapproachesinfinity):

yeah that's a series that i wrote? don't got what you're saying, use the drawing tool

OpenStudy (anonymous):

\[\sum_{n=1}^{\infty}\frac{1}{n^3+n^2}\]??

OpenStudy (anonymous):

|dw:1407205520091:dw|

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