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calculus 2
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\[\sum n =1 \to infinity (1/(n^3+n^2)\]
explain please?
the answer should be ((pi^2)/6)-1 at least thats what wolfram alpha says. i am trying to figure out how
is that like this? \[\sum_{1}^{\infty}\frac{ 1}{ n ^{3} +n ^{2}}\]
no where its 1 its n=1 its a series problem
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yeah that's a series that i wrote? don't got what you're saying, use the drawing tool
\[\sum_{n=1}^{\infty}\frac{1}{n^3+n^2}\]??
|dw:1407205520091:dw|
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