Ask your own question, for FREE!
Mathematics 17 Online
OpenStudy (anonymous):

calculus 2

OpenStudy (anonymous):

\[\sum n =1 \to infinity (1/(n^3+n^2)\]

OpenStudy (anonymous):

explain please?

OpenStudy (anonymous):

the answer should be ((pi^2)/6)-1 at least thats what wolfram alpha says. i am trying to figure out how

OpenStudy (xapproachesinfinity):

is that like this? \[\sum_{1}^{\infty}\frac{ 1}{ n ^{3} +n ^{2}}\]

OpenStudy (anonymous):

no where its 1 its n=1 its a series problem

OpenStudy (xapproachesinfinity):

yeah that's a series that i wrote? don't got what you're saying, use the drawing tool

OpenStudy (anonymous):

\[\sum_{n=1}^{\infty}\frac{1}{n^3+n^2}\]??

OpenStudy (anonymous):

|dw:1407205520091:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Mari103: How to pop out like a Jacc In the box
15 minutes ago 0 Replies 0 Medals
Breathless: Spooky witch but cute
7 hours ago 3 Replies 0 Medals
Arriyanalol: help
6 hours ago 10 Replies 2 Medals
Arriyanalol: @tinydinoUwU stop trying to find a argument u blad lil boy
1 day ago 5 Replies 4 Medals
Jaded012023: Please tell me what you all think of this song
9 hours ago 6 Replies 1 Medal
Arriyanalol: bro how
9 hours ago 2 Replies 3 Medals
Arriyanalol: cant wait for the new bluey movie in 2027
1 day ago 12 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!