Mathematics
8 Online
OpenStudy (anonymous):
WIll fan and medal!
Solve the following equation:
\sqrt{x+4}=3x-12
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OpenStudy (anonymous):
x = 5
OpenStudy (anonymous):
but how?
OpenStudy (anonymous):
you could graph it or solve the equation
OpenStudy (anonymous):
i uh, need help with the steps to solve the equation :P
OpenStudy (anonymous):
okay work me through what you have done so far
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OpenStudy (anonymous):
\[\left( \sqrt{x+4}^2 \right) = \left( 3x-12 \right)^2\]
x+4 = 9x - 144
OpenStudy (anonymous):
your close, you made a mistake simplifying the right hand side of your equation, it should be: (3x-12)(3x-12)
OpenStudy (anonymous):
k, so i got x + 4 = 9x^2 - 72x + 144
OpenStudy (anonymous):
good
OpenStudy (anonymous):
now subtract 4 and x from both sides
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OpenStudy (anonymous):
so you get 0 on the left hand side of your equation
OpenStudy (anonymous):
0 = 9x^2 - 72 + 140
OpenStudy (anonymous):
and then i graph that?
OpenStudy (anonymous):
nope you made a mistake
OpenStudy (anonymous):
where did i go wrong..?
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OpenStudy (anonymous):
remember you have to foil
OpenStudy (anonymous):
it should be: 0 = 9x^2 - 73x + 140
OpenStudy (anonymous):
you forgot to subtract the x
OpenStudy (anonymous):
then all you have to do is plug it into the quadratic formula
OpenStudy (anonymous):
\[x = \frac{-73\pm \sqrt{(-73)^2 - 4 (9) (140)}\ }{ 18 }\]
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OpenStudy (anonymous):
k, that;s how far i got
OpenStudy (anonymous):
yup now solve both the equations with the + and the -
OpenStudy (anonymous):
i keep on getting fractions as answer when i type it in the calc..
OpenStudy (anonymous):
one awnser should be a fraction
OpenStudy (anonymous):
the other should be 5
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OpenStudy (anonymous):
i got -5...
OpenStudy (anonymous):
nope its 5
OpenStudy (anonymous):
lol alright :) thanks for your help!