1. If cos Θ is negative and tan Θ is positive, then sin Θ is negative.
cos Θ = -2/5
cos Θ = adj/hyp
(-2)² + (opp)² = 5²
opp = √21
sin Θ = (-√21)/5

2. (-5, 7) is in the 2nd quadrant, so sin Θ is positive. Θ is with the x-axis, so -5 is the adjacent side and 7 is the opposite side.
(-5)² + 7² = (hyp)²
hyp = √74
sin Θ = (7√74)/74

3. (12,-5) is in the 4th quadrant, so cos Θ is positive. Θ is with the x-axis, so 12 is adj and -5 is opp. hyp is 13.
cos Θ = 12/13.

4. 5π/6 is in the 2nd quadrant, so sin Θ is positive and cos Θ and tan Θ are both negative. The reference angle is the s

Question

1. If cos Θ is negative and tan Θ is positive, then sin Θ is negative.
cos Θ = -2/5
cos Θ = adj/hyp
(-2)² + (opp)² = 5²
opp = √21
sin Θ = (-√21)/5

2. (-5, 7) is in the 2nd quadrant, so sin Θ is positive. Θ is with the x-axis, so -5 is the adjacent side and 7 is the opposite side.
(-5)² + 7² = (hyp)²
hyp = √74
sin Θ = (7√74)/74

3. (12,-5) is in the 4th quadrant, so cos Θ is positive. Θ is with the x-axis, so 12 is adj and -5 is opp. hyp is 13.
cos Θ = 12/13.

4. 5π/6 is in the 2nd quadrant, so sin Θ is positive and cos Θ and tan Θ are both negative. The reference angle is the s

anonymous · Answer

These are the test answers for 10.02 if anyone needs them