Question

Help please!

Write x^2 - 8x + 13 = 0 in the form (x - a)^2 = b, where a and b are integers.

(x - 4)^2 = 3

(x - 3)^2 = 2

(x - 2)^2 = 1

(x - 1)^2 = 4

Answer 1

explain it maybe? so i can understand for future questions /.\

Answer 2

so you have to complete the square.

Answer 3

To complete the square, add and subtract (co-efficient of 'x' /2)^2 first

Answer 4

for
x^2 - 8x + 13 = 0

what is the co-efficient of x ?

Answer 5

1?

Answer 6

for x^2 its 1
because
x^2 =1x^2

what about 'x' ?
which number is before 'x' (not x^2)

Answer 7

oh 8

Answer 8

close
its -8

now next step is to divide it by 2

Answer 9

divide what by 2

Answer 10

sorry im slow /.\

Answer 11

-8

"add and subtract (co-efficient of 'x' /2)^2"

so
add and subtract (-8 /2)^2

so

add and subtract (-4)^2 = ... ?

Answer 12

im confused :/

Answer 13

with what ?

Answer 14

-8-2 right?

Answer 15

-8-2=-10?

Answer 16

-8/2

Answer 17

subtracting or dividing..............

Answer 18

i never said subtracting by 2

its dividing by 2

Answer 19

yea you did :/ up there
but -4?

Answer 20

yes, -4
now square it

Answer 21

-4^2?
is it the first answer choice

Answer 22

whats the value of
\(\large (-4)^2 =..\)

Answer 23

what do you mean

Answer 24

asking you the value of (-4)^2
(-4)*(-4) = ..

Answer 25

16?

Answer 26

yes
so we add and subtract 16

\(x^2 -8x+16 + (13-16) = 0\)

Answer 27

now
\(x^2 -8x+16\) is the perfect square of
\((x-4)^2 \)
{because 16 is the square of 4}

Answer 28

so we have
\((x-4)^2 -3=0\)

Answer 29

see the steps and ask doubts

Answer 30

thanks

Answer 31

welcome ^_^