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How can exopential equations with unequal bases be solved Ex:64=3^(4x)
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\(64\) has no base
well take the log and solve
\[b^x=A\iff x=\frac{\log(A)}{\log(b)}\] so \[3^{4x}=64\iff 4x=\frac{\log(64)}{\log(3)}\]
Oh ok
Is that it or are their more steps?
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