Mathematics
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OpenStudy (anonymous):
Given sin x=-4/5 and x is in the third quadrant, what is the value of tan(x/2)
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OpenStudy (xapproachesinfinity):
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OpenStudy (anonymous):
Do I use the pythagorean theorem to solve it?
OpenStudy (xapproachesinfinity):
Correct!
OpenStudy (xapproachesinfinity):
first find the missing adjacent part using pyth thm
OpenStudy (anonymous):
Ok, thanks for the help.
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OpenStudy (anonymous):
So, I got 6.40? is that correct?
OpenStudy (xapproachesinfinity):
Or you can just find the angle using inverse of sin
sinx=-4/5 ===> x=sin^-1(-4/5)
find the x and divide it by 2
then do tan(x/2)
OpenStudy (xapproachesinfinity):
I'm not sure, i didn't do calculation im just telling how to do this
OpenStudy (anonymous):
Ok, thanks for leading me to the answer.
OpenStudy (xapproachesinfinity):
yw!
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OpenStudy (anonymous):
I got 0.23 as a final answer, is that correct?
OpenStudy (xapproachesinfinity):
i got -1/2 did you do it by degrees or radians?
OpenStudy (anonymous):
Degree
OpenStudy (xapproachesinfinity):
You should get what i got?
what did you do?
OpenStudy (xapproachesinfinity):
-0.499 round it to -0.5
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OpenStudy (xapproachesinfinity):
i got it like that!
OpenStudy (anonymous):
I took the inverse of sin (4/5) then I divided that by two, then I plugged that into tan(x/2)
OpenStudy (anonymous):
It said the correct answer was -2, but thanks for the help.
OpenStudy (xapproachesinfinity):
not 4/5! -4/5
OpenStudy (anonymous):
Oh... that's why I didn't get it