Mathematics
9 Online
OpenStudy (anonymous):
stuck
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OpenStudy (anonymous):
OpenStudy (australopithecus):
have you drawn a diagram?
OpenStudy (anonymous):
ye
OpenStudy (anonymous):
oh 6ix min?
OpenStudy (australopithecus):
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OpenStudy (australopithecus):
so in this case you can use SOH CAH TOA to solve for the hypotenuse, which will tell you the distance of the ride
OpenStudy (australopithecus):
you know SOH CAH TOA right?
OpenStudy (anonymous):
ty <3
OpenStudy (australopithecus):
No problem if you have any other questions regarding this problem feel free to ask
OpenStudy (anonymous):
sin31/902=.00057
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OpenStudy (australopithecus):
sin(x) = 902/hypotenuse
=
sin(x)(hypotenuse) = 902
=
902/sin(x) = hypotenuse
OpenStudy (australopithecus):
be careful with your algebra dont skip steps
OpenStudy (australopithecus):
if you get a really small number and are expecting a very large number you just need to flip the fraction most of the time, but even then
OpenStudy (australopithecus):
remember what division is
OpenStudy (australopithecus):
it is how many times the denominator can go into the numerator
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OpenStudy (anonymous):
902/sinx?
OpenStudy (australopithecus):
902/sin(32)
because,
902/h = sin(32)
h*sin(32) = 902
h = 902/sin(32)
you calculated
1/h = sin(32)/902
OpenStudy (australopithecus):
make sense?
OpenStudy (australopithecus):
sorry for putting the x there my brain is just dead atm
OpenStudy (australopithecus):
and that should be 31 not 32 lol
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OpenStudy (australopithecus):
to get the final answer remember that you have to figure out the amount of time it takes to travel that distance
OpenStudy (anonymous):
so that answer divided by 155 ft per minute?
OpenStudy (australopithecus):
yup :)
OpenStudy (anonymous):
thanks teacher
OpenStudy (australopithecus):
feet cancel out that way and you are left with minutes
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OpenStudy (australopithecus):
No problem