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Mathematics 9 Online
OpenStudy (anonymous):

stuck

OpenStudy (anonymous):

OpenStudy (australopithecus):

have you drawn a diagram?

OpenStudy (anonymous):

ye

OpenStudy (anonymous):

oh 6ix min?

OpenStudy (australopithecus):

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OpenStudy (australopithecus):

so in this case you can use SOH CAH TOA to solve for the hypotenuse, which will tell you the distance of the ride

OpenStudy (australopithecus):

you know SOH CAH TOA right?

OpenStudy (anonymous):

ty <3

OpenStudy (australopithecus):

No problem if you have any other questions regarding this problem feel free to ask

OpenStudy (anonymous):

sin31/902=.00057

OpenStudy (australopithecus):

sin(x) = 902/hypotenuse = sin(x)(hypotenuse) = 902 = 902/sin(x) = hypotenuse

OpenStudy (australopithecus):

be careful with your algebra dont skip steps

OpenStudy (australopithecus):

if you get a really small number and are expecting a very large number you just need to flip the fraction most of the time, but even then

OpenStudy (australopithecus):

remember what division is

OpenStudy (australopithecus):

it is how many times the denominator can go into the numerator

OpenStudy (anonymous):

902/sinx?

OpenStudy (australopithecus):

902/sin(32) because, 902/h = sin(32) h*sin(32) = 902 h = 902/sin(32) you calculated 1/h = sin(32)/902

OpenStudy (australopithecus):

make sense?

OpenStudy (australopithecus):

sorry for putting the x there my brain is just dead atm

OpenStudy (australopithecus):

and that should be 31 not 32 lol

OpenStudy (australopithecus):

to get the final answer remember that you have to figure out the amount of time it takes to travel that distance

OpenStudy (anonymous):

so that answer divided by 155 ft per minute?

OpenStudy (australopithecus):

yup :)

OpenStudy (anonymous):

thanks teacher

OpenStudy (australopithecus):

feet cancel out that way and you are left with minutes

OpenStudy (australopithecus):

No problem

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