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dealing with the zero-product property..
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apply the zero-product property to solve the following equations:
\[x(2x+5)=0\]
\[5(x-1)(x+4)(2x-3)=0\]
they're both different problems btw
If x(2x+5)=0 then either x = 0 or 2x+5 = 0
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solve 2x+5 = 0 for x to get 2x+5 = 0 2x+5-5 = 0-5 2x = -5 2x/2 = -5/2 x = -5/2
So if x(2x+5)=0, then x = 0 or x = -5/2
5(x-1)(x+4)(2x-3)=0 breaks up into x-1=0 or x+4=0 or 2x-3=0 solve each equation for x to get your three solutions
so then the two answer choices will be x=0 and x=-5/2 correct?
for x(2x+5)=0, yes
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@jim_thompson5910 is is x=1 x=-4 and x=3/2 ?
for 5(x-1)(x+4)(2x-3)=0 , yep
thank you @jim_thompson5910
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