Calculus particle question:
A particle moves along the x-axis so that at any time t, 0

Question

Calculus particle question:
A particle moves along the x-axis so that at any time t, 0<t<5, its velocity is given by v(t)=sin(t)+ e^(-t).

Find all values of t for which the particle is at rest.

cwrw238 · Answer

at rest v(t)  = 0

sin t + e ^(-t) =  0

solve for t

avanti · Answer

yeah i tried to but i don't know how to solve for t

cwrw238 · Answer

differentiating will give the acceleration at time t

cwrw238 · Answer

you could solve it by gralhing

cwrw238 · Answer

you sure you have the formula right
I've just graphed it on my calculator
theres no value of v(t) = 0 for  0 < t < 5

avanti · Answer

thats what i was getting too. the question is correct so would that mean that there are no values for which it is at rest?

cwrw238 · Answer

oh  hold on I've used degrees  on the graph  - should be radians

avanti · Answer

oh me too... im getting something around 3.18 but is there a way to see the exact value?

cwrw238 · Answer

my calculator gives  t = 3.18 , 6.28

cwrw238 · Answer

i dont think so  pi radians = 3.1416 so its a bit above this

avanti · Answer

okay thanks so much for all your help!

cwrw238 · Answer

yw