OpenStudy (anonymous):

Number system!!!!
xy is a number that is divided by ab where xy

OpenStudy (anonymous):

since., \[\frac{ xy }{ ab } = 0\] And \[xy < ab\] So they answer is very simple \[\frac{ xy }{ ab } = 0 => \frac{ xy }{ 1} = 0 \times ab = 0\] so ab can be any no where xy is 0 and 0 divided by any no is either zero or considered infinity Therfore ab can also be taken as 1 @aryandecoolest

3 years ago
OpenStudy (anonymous):

but answer is 99

3 years ago
OpenStudy (anonymous):

any number that divides 0 always yields zero no matter what that number is..

3 years ago
OpenStudy (anonymous):

See : \[\frac{ xy }{ ab } = 0.xyxyxyxyxyx.......\] where, \[xy < ab\] we know that quantity : 0.xyxyxyxyxyxy........ is Irrational Therefore it can also be written as: \[\frac{ xy }{ 100 } +\frac{ xy }{ 1000 } + \frac{ xy }{ 10000 } + \frac{ xy }{100000}+...\] Now takin' \[\frac{ xy }{ 100 }\] as common Therefore: \[\frac{ xy }{ 100 }\left( 1 + \frac{ 1 }{ 10 } + \frac{ 1 }{ 100 } + \frac{ 1 }{ 1000 } + .. \right)\] \[=\frac{ xy }{ 100} \times \frac{ 1 }{ (1 - 100)}\] Remember convergence/divergence of power series ! \[= \frac{ xy }{ 99 }\] Therefore ,we conclude that: \[\frac{ xy }{ ab } = 0.xyxyxyxyxy... = \frac{ xy }{ 99}\] Therefore ab is: \[ab = 99\] @aryandecoolest

3 years ago
OpenStudy (anonymous):

oh!!!(deep sigh) :)

3 years ago
OpenStudy (anonymous):

why sigh?

3 years ago