Question

what are the solution of x^2-4x+5=0? anyone could please help

Answer 1

imaginary numbers

Answer 2

subtract 1 from both sides, and try to complete the square.

Answer 3

i just started this idk anything

Answer 4

What course is this, ALGEBRA 1 ?

Answer 5

If so, say no solutions.

Answer 6

\(\Huge\bf \color{yellow}{Welcome~to~OpenStudy!!}\hspace{-310pt}\color{cyan}{Welcome~to~OpenStudy!!}\hspace{-307.1pt}\color{midnightblue}{Welcome~to~\color{purple}{Open}}\color{blue}{Study!!!!}\)
@SolomonZelman Can teach you!!:)

Answer 7

algebra 2

Answer 8

\[x ^{2}-4x+5\]
find two numbers which when you multiply give you 5 and when you add give you -4

Answer 9

\(\normalsize\color{blue}{ x^2-4x+5=0}\)
\(\normalsize\color{blue}{ x^2-4x+5 \color{red}{-1}=0\color{red}{-1}}\)
\(\normalsize\color{blue}{ x^2-4x+4=-1}\)
\(\normalsize\color{blue}{ (x-2)^2=-1}\)
\(\normalsize\color{blue}{ x-2=\sqrt{-1}}\)

Answer 10

For you, it will be no solutions, or err imput.
(on an imaginary level though....
\(\normalsize\color{blue}{ x-2=± \sqrt{-1}}\)
\(\normalsize\color{blue}{ x-2=±i}\)
\(\normalsize\color{blue}{ x=2±i}\)

Answer 11

nyc method @SolomonZelman

Answer 12

Yes, I am kind of completing the square, but I am skipping the 1st step of setting it to ax²+bx=-c, I just start with ax²+bx+c=d, and add whatever number that would make it a perf. square.

Answer 13

so how bout for this one

Answer 14

x^2-2x+37=0?

Answer 15

no solution

subtract 36 from both sides

Answer 16

but, you will get (imaginary solutions) x= -1±6i

Answer 17

why 36...why not 1? do you subtract a number that is also a perfect square?

Answer 18

Yes, that is what I do, I make the left hand side into a perfect square.

Answer 19

it is completing the square, without a step.
My teacher forgave me that :)

Answer 20

x=1+6i x=1-6i ?

Answer 21

or x=6i x=-6i

Answer 22

yes, -1+6i, or -1-6i

If you haven't learned about imaginary numbers yet, don't say this though. Then, just say no solution.

Answer 23

okay thanks

Answer 24

x^2-3x+3=0?

Answer 25

Anytime

Answer 26

x²-3x+3=0

use the quadratic formula, or complete the square. (you can't factor it, because the discriminant isn't a perfect square)

Answer 27

Can you finish it, or need help ?

Answer 28

i tried it but i can't

Answer 29

\(\LARGE\color{blue}{ x= \frac{-(-3)± \sqrt{(-3)^2-4(1)(3)}}{2(1)} }\)

\(\LARGE\color{blue}{ x= \frac{3± \sqrt{9-12}}{2} }\)

\(\LARGE\color{blue}{ x= \frac{3± \sqrt{-3}}{2} }\)

Answer 30

So, no real number solutions, but
x= (3-i√3) / 2 or (3+i√3) / 2

Answer 31

sorry for a late reply.

Answer 32

got you

Answer 33

the discriminant of a quadratic equation is negative. one solution is 3+4i. what is the other solution ?

Answer 34

3+4i is not one of the solutions, I posted the solutions and the way to obtain them.
You got right though, that

negative discriminant = imaginary solution(s)
discriminant 0 = 1 real solutions (or saying that the equation is really a line)
positive discriminant = 2 real solutions.