Question

If the center of a circle is (0, 0) and the radius is the square root of 7 , the equation of the circle is: x^2+y^2=7. Is the answer true?

Answer 1

Very true.. :)

Answer 2

Great, thank you. Also, for this equation of a circle (x-2)^2+(y+3)^2=6 the radius of the circle is square root of 6 or is it 36?

Answer 3

sqrt{6}

Answer 4

Thank you very much @waterineyes :)

Answer 5

Circle equation is:

\[(x-h)^2 + (y-k)^2 = r^2\]

Where r is the radius..

So, comparing :

\[r^2 = 6 \implies \color{blue}{r = \sqrt{6}}\]