If the center of a circle is (0, 0) and the radius is the square root of 7 , the equation of the circle is: x^2+y^2=7. Is the answer true?

Question

If the center of a circle is (0, 0) and the radius is  the square root of 7 , the equation of the circle is: x^2+y^2=7. Is the answer true?

anonymous · Answer

Very true.. :)

anonymous · Answer

Great, thank you. Also, for this equation of a circle (x-2)^2+(y+3)^2=6 the radius of the circle is square root of 6 or is it 36?

anonymous · Answer

sqrt{6}

anonymous · Answer

Thank you very much @waterineyes :)

anonymous · Answer

Circle equation is:

$$(x-h)^2 + (y-k)^2 = r^2$$

Where r is the radius..

So, comparing :

$$r^2 = 6 \implies \color{blue}{r = \sqrt{6}}$$